JEE Main 20 July 2021 Shift 1 Solved Paper

At neutral point g = 0 so graph (C) is correct

Given,
Acceleration due to gravity on Earth, gE=10m∕s2
and acceleration due to gravity on Mars, gM=4m∕s2
We know that,
gE (at height h)=g‌Earth ‌(1−‌

2h

R

)
∴ Weight at Earth,
mgE=100×10=1000N
As the spaceship moves far away from Earth, the value of gE decreases to zero at a point where gE+gM=0 and hence weight will also be zero.
This point is called neutral point and is shown by graph (c) in the given figure.
Then, gE increases 4ms−2 at Mars surface and weight becomes 400N which is also exhibited by graph (c).