JEE Main 2 Apr 2025 Shift 2 Paper
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Question : 24 of 75
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Let y = y ( x ) be the solution of the differential equation
+ 2 y s e c 2 x = 2 s e c 2 x + 3 tan x â‹… s e c 2 x s u c h that y ( 0 ) =
. Then 12 ( y (
) − e − 2 ) is equal to _ _ _ _ _ .
[2 Apr 2025 Shift 2]
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