JEE Main 18 March 2021 Shift 2 Solved Paper

Section: Mathematics

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Question : 79 of 90

Marks: +1, -0

The area bounded by the curve 4y2=x2(4−x)(x−2) is equal to

[18 Mar 2021 Shift 2]

‌
π
8
‌
3π
8
‌
3π
2
‌
π
16

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