Let g(x)=\int_{0}^{x} f(t) d t, where f is continuous function in [0,3] such that \frac{1}{3} \leq f(t) \leq 1 for all t \in[0,1] and 0 \leq f(t) \leq \frac{1}{2} for all t \in(1,3]. The largest possible interval in which g(3) lies is [18 Mar 2021 Shift 2]

JEE Main 18 March 2021 Shift 2 Solved Paper

Section: Mathematics

Question : 68 of 90

Marks: +1, -0

Let g(x)=

∫

f(t)dt, where f is continuous function in [0,3] such that ‌

≤f(t)≤1 for all t∈[0,1] and 0≤f(t)≤‌

for all t∈(1,3]. The largest possible interval in which g(3) lies is

[18 Mar 2021 Shift 2]

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