The gas phase reaction 2 A(g) ⇌ A_{2}(g) at 400 {K} has ∆ G^{\circ}=+25.2 {kJ} {mol}^{-1}. The equilibrium constant K_{C} for this reaction is .......... \times 10^{-2}. (Round off to the nearest integer). [Use : R=8.3 {J} {mol}^{-1} {K}^{-1}, \ln 10=2.3 ] \log _{10^{2}} 2=0.30,1 {atm}=1 {bar}] [antilog (-0.3)=0.501 ] [18 Mar 2021 Shift 2]

JEE Main 18 March 2021 Shift 2 Solved Paper

Section: Chemistry

Question : 55 of 90

Marks: +1, -0

The gas phase reaction
2A(g)⇌A2(g)
at 400K has ∆G∘=+25.2kJmol−1. The equilibrium constant KC for this reaction is .......... ×10−2. (Round off to the nearest integer).
[Use : R=8.3Jmol−1K−1,ln‌10=2.3 ] log1022=0.30,1atm=1bar] [antilog (−0.3)=0.501 ]

[18 Mar 2021 Shift 2]

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