JEE Main 18 March 2021 Shift 2 Solved Paper

At the balanced condition of the
Wheatstone bridge, ‌

R

S

=‌

L1

L−L1

⇒‌‌‌

12

6

=‌

x

72−x

⇒‌‌x=48cm
∴ The galvanometer jockey is placed at P on AB at a distance of 48 cm from the A.
So, the value of the x to the nearest integer is 48 .