JEE Main 18 March 2021 Shift 2 Solved Paper
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Question : 26 of 90
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The radius of a sphere is measured to be ( 7.50 ± 0.85 ) c m . Suppose the percentage error in its volume is x . The value of x to the nearest x , is ............. .
[18 Mar 2021 Shift 2]
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