The function of time representing a simple harmonic motion with a period of \frac{\pi}{\omega} is [18 Mar 2021 Shift 2]

Correct Answer is : 3cos(π4−2ωt)

\sin (\omega t)=\cos (\omega t)

\cos (\omega t)+\cos (2 \omega t)+\cos (3 \omega t)

3 \cos (\frac{\pi}{4}-2 \omega t)

JEE Main 18 March 2021 Shift 2 Solved Paper

Section: Physics

Question : 14 of 90

Marks: +1, -0

The function of time representing a simple harmonic motion with a period of ‌

[18 Mar 2021 Shift 2]

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