JEE Main 18 March 2021 Shift 1 Solved Paper
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The time period of a simple pendulum is given by T = 2 π √ 1 / g . The measured value of the length of pendulum is 10 c m known to a 1 m m accuracy. The time for 200 oscillations of the pendulum is found to be 100 s using a clock of 1 s resolution. The percentage accuracy in the determination of g using this pendulum is x . The value of x to the nearest integer is
[18 Mar 2021 Shift 1]
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