JEE Main 18 March 2021 Shift 1 Solved Paper

Section: Mathematics
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Question : 63 of 90
 
Marks: +1, -0
Let (1+x+2x2)20=a0+a1x+a2x2+...+a40x40, then a1+a3+a5+...+a37 is equal to
[18 Mar 2021 Shift 1]
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