JEE Main 18 March 2021 Shift 1 Solved Paper

Section: Mathematics

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Question : 61 of 90

Marks: +1, -0

The differential equation satisfied by the system of parabolas y2=4a(x+a) is

[18 Mar 2021 Shift 1]

y(‌
dy
dx
)2−2x(‌
dy
dx
)−y=0
y(‌
dy
dx
)2−2x(‌
dy
dx
)+y=0
y(‌
dy
dx
)2+2x(‌
dy
dx
)−y=0
y(‌
dy
dx
)+2x(‌
dy
dx
)−y=0

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