JEE Main 18 March 2021 Shift 1 Solved Paper

Given,
The power gain of an n−p−n transistor,
P=106
The input circuit of the resistance,
r=100Ω
The output load resistance of the circuit,
R=10kΩ=10000Ω
We know that,
Power gain of common emitter amplifier,
P=‌

β2R

r

‌ Here, ‌‌106‌‌=‌

β2×10000

100

⇒‌β‌‌=100