JEE Main 18 March 2021 Shift 1 Solved Paper

Given
The final pressure of the adiabatic process, pf=200N∕m2
The initial pressure of the adiabatic process, pi=100N∕m2
The initial volume of the adiabatic process, V1=4m3
The final volume of the adiabatic process, Vf=3m3
We know that, for an adiabatic process
W=‌

pfVf−piVi

1−γ

⇒‌‌W=‌

200(3)−(100)(4)

1−1.4

⇒‌‌W=−500J
So, the work done by an adiabatic process is 500J and negative sign represents the work done on the system.