Let f:[-1,1] \to R be defined as f(x)=a x^{2}+b x+c for all x \in[-1,1], where a, b, c \in R, such that f(-1)=2, f^{'}(-1)=1 and for x \in(-1,1) the maximum value of f^{' '}(x) is \frac{1}{2}. If f(x) \leq \alpha, x \in[-1,1], then the least value of \alpha is equal to [17 Mar 2021 Shift 2]

JEE Main 17 March 2021 Shift 2 Solved Paper

Section: Mathematics

Question : 82 of 90

Marks: +1, -0

Let f:[−1,1]→R be defined as f(x)=ax2+bx+c for all x∈[−1,1], where a,b,c∈R, such that f(−1)=2,f′(−1)=1 and for x∈(−1,1) the maximum value of f′′(x) is ‌

. If f(x)≤α,x∈[−1,1], then the least value of α is equal to

[17 Mar 2021 Shift 2]

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