If the equation of plane passing through the mirror image of a point (2,3,1) with respect to line \frac{x+1}{2}=\frac{y-3}{1}=\frac{z+2}{-1} and containing the line \frac{x-2}{3}=\frac{1-y}{2}=\frac{z+1}{1} is \alpha x+\beta y+\gamma z=24, then \alpha+\beta+\gamma is equal to [17 Mar 2021 Shift 2]

JEE Main 17 March 2021 Shift 2 Solved Paper

Section: Mathematics

Question : 80 of 90

Marks: +1, -0

If the equation of plane passing through the mirror image of a point (2,3,1) with respect to line ‌

x+1

=‌

y−3

=‌

z+2

−1

and containing the line ‌

x−2

=‌

1−y

=‌

z+1

is αx+βy+γz=24, then α+β+γ is equal to

[17 Mar 2021 Shift 2]

Go to Question:

Prev Question

Next Question