JEE Main 17 March 2021 Shift 2 Solved Paper

Section: Mathematics

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Question : 77 of 90

Marks: +1, -0

The value of the limit

lim

θ→0

‌

tan(πcos2θ)

sin(2πsin2θ)

is equal to

[17 Mar 2021 Shift 2]

−‌
1
2
−‌
1
4
0
‌
1
4

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