The disc of mass M with uniform surface mass density \sigma is shown in the figure. The centre of mass of the quarter disc (the shaded area) is at the position \frac{x}{3} \frac{a}{\pi}, \frac{x}{3} \frac{a}{\pi}, where x is ............ (Round off to the nearest integer) ( a is an area as shown in the figure) [17 Mar 2021 Shift 2]

JEE Main 17 March 2021 Shift 2 Solved Paper

Section: Physics

Question : 27 of 90

Marks: +1, -0

The disc of mass M with uniform surface mass density σ is shown in the figure. The centre of mass of the quarter disc (the shaded area) is at the position ‌

‌

,‌

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, where x is ............ (Round off to the nearest integer) ( a is an area as shown in the figure)

[17 Mar 2021 Shift 2]

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