An AC current is given by I=I_{1} \sin \omega t+I_{2} \cos \omega t. A hot wire ammeter will give a reading [17 Mar 2021 Shift 1]

Correct Answer is : √l12+I222

\sqrt{ {I_{1}^{2}-I_{2}^{2}}/{2}}

\sqrt{ {l_{1}^{2}+I_{2}^{2}}/{2}}

JEE Main 17 March 2021 Shift 1 Solved Paper

Section: Physics

Question : 8 of 90

Marks: +1, -0

An AC current is given by I=I1‌sin‌ω‌t+I2‌cos‌ω‌t. A hot wire ammeter will give a reading

[17 Mar 2021 Shift 1]

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