JEE Main 17 March 2021 Shift 1 Solved Paper

Given, current, I=10A
Cross-sectional area, A=5mm2=5×10−6m2
Drift velocity, vd=2×10−3ms−1
The value of current flowing through a conductor can be given by
I=neAvd....(i)
where, n= number of free electrons
and e= charge on an electron
Putting all the given values in Eq. (i) we get
10=n×1.6×10−19×5×10−6×2×10−3
⇒‌‌n=‌

10

1.6×10−19×5×10−6×2×10−3

=0.625×1028=625×1025