JEE Main 17 March 2021 Shift 1 Solved Paper

It is given that the system is assumed to be in steady circular motion with constant angular velocity ω.
We know that L=m(r×v)
where,
L= angular momentum,
v= velocity of the particle,
m= mass of the particle
and r= radius of the circular path traced by the particle.
Since, LA is the angular momentum of M about point A which lies in positive z-direction. Therefore, with respect to point A, we will get the direction of L along positive Z-axis and of constant magnitude of mvr.
Since, LB is the angular momentum of M about point B, so with respect to point B, we will get the constant magnitude of L but its direction will be continuously changing. Hence, option (d) is correct.