If the foot of the perpendicular from point (4,3,8) on the line L_{1}: \frac{x-a}{1}=\frac{y-2}{3}=\frac{z-b}{4}, I \neq 0 is (3,5,7), then the shortest distance between the line L_{1} and line L_{2}: \frac{x-2}{3}=\frac{y-4}{4}=\frac{z-5}{5} is equal to [16 Mar 2021 Shift 2]

JEE Main 16 March 2021 Shift 2 Solved Paper

Section: Mathematics

Question : 78 of 90

Marks: +1, -0

If the foot of the perpendicular from point (4,3,8) on the line L1:‌

x−a

=‌

y−2

=‌

z−b

, I≠0 is (3,5,7), then the shortest distance between the line L1 and line L2:‌

x−2

=‌

y−4

=‌

z−5

is equal to

[16 Mar 2021 Shift 2]

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