JEE Main 16 March 2021 Shift 2 Solved Paper

Given,
Linear charge density, λ=8nC/m=8×10−9C/m
The relation between surface charge density and linear charge density can be given as
‌

2kλ

r

=‌

σ

ε0

.....(i)
where,
k= Coulomb's constant,
λ= linear charge density,
σ= surface charge density,
ε0= absolute electrical permittivity of free space
and r= distance.
Substituting the values in Eq. (i), we get
σ=‌

2kλε0

r

=‌

2×9×109×8×10−9×8.85×10−12

3

=0.424×10−9Cm−2=0.424nCm−2