JEE Main 16 March 2021 Shift 1 Solved Paper

From ideal gas equation,
pV=(n1+n2+n3)RT
where, n1= number of moles of oxygen =‌

16

32

n2= number of moles of nitrogen =‌

28

28

n3= number of moles of carbon dioxide =‌

44

44

=‌

5

2

RT⇒p=‌

5

2

‌

RT

V

This is the required pressure of the mixture of the gases.