JEE Main 16 Apr 2018 Shift 1 Solved Paper

Section: Mathematics

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Question : 74 of 90

Marks: +1, -0

If

∫

tanx

1+tanx+tan2x

dx=x−

K

√A

tan−1(

Ktanx+1

√A

)+C

, (C is a constant of integration), then the ordered pair (K, A) is equal to :

[Main 16 April 2018 S1]

(2,1)
(−2,3)
(2,3)
(−2,1)

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