JEE Main 16 Apr 2018 Shift 1 Solved Paper

Section: Mathematics

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Question : 68 of 90

Marks: +1, -0

Let

1

x1

,

1

x2

,...,

1

xn

(xi≠0for i=1,2,...,n) be in A.P. such that x1=4 and x21=20.If n is the least positive integer for which xn>50 then

n

∑

i=1

(

1

xi

) is equal to:

[Main 16 April 2018 S1]

1
8
3
13
8
13
4

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