JEE Main 15 Apr 2018 Shift 2 Solved Paper

Section: Mathematics

Question : 69 of 90

Marks: +1, -0

A normal to the hyperbola, 4x2−9y2=36 meets the co-ordinate axes x and y at A and B, respectively. If the parallelogram OABP ( O being the origin) is formed, then the locus of P is :-

[15 Apr 2018 Shift 2]

9x2+4y2=169
4x2−9y2=121
4x2+9y2=121
9x2−4y2=169

Validate

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