Statement p: The value of \sin 120^{\circ} can be derived by taking \theta=240^{\circ} in the equation 2 \sin \frac{\theta}{2}=\sqrt{1+ \sin \theta}-\sqrt{1- \sin \theta}. Statement q : The angles A , B , C and D of any quadrilateral A B C D satisfy the equation \cos (\frac{1}{2}(A+C)) +\cos (\frac{1}{2}(B+D)) =0 Then the truth values of p and q are respectively : [15 Apr 2018 Shift 2]

JEE Main 15 Apr 2018 Shift 2 Solved Paper

Section: Mathematics

Question : 64 of 90

Marks: +1, -0

Statement p: The value of sin‌120∘ can be derived by taking θ=240∘ in the equation 2sin‌‌

=√1+sin‌θ−√1−sin‌θ.
Statement q : The angles A,B,C and D of any quadrilateral ABCD satisfy the equation cos(‌

(A+C))+cos(‌

(B+D))=0
Then the truth values of p and q are respectively :

[15 Apr 2018 Shift 2]

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