Two 5 molal solutions are prepared by dissolving a non-electrolyte non-volatile solute separately in the solvents X and Y . The molecular weights of the solvents are M_X and M_Y, respectively where M _{ X }=\frac{3}{4} M _{ Y }. The relative lowering of vapour pressure of the solution in X is " m " times that of the solution in Y . Given that the number of moles of solute is very small in comparison to that of solvent, the value of " m " is - [15 Apr 2018 Shift 2]

JEE Main 15 Apr 2018 Shift 2 Solved Paper

Section: Chemistry

Question : 51 of 90

Marks: +1, -0

Two 5 molal solutions are prepared by dissolving a non-electrolyte non-volatile solute separately in the solvents X and Y . The molecular weights of the solvents are MX and MY, respectively where MX=‌

MY. The relative lowering of vapour pressure of the solution in X is " m " times that of the solution in Y . Given that the number of moles of solute is very small in comparison to that of solvent, the value of " m " is -

[15 Apr 2018 Shift 2]

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