JEE Main 15 Apr 2018 Shift 2 Solved Paper

Section: Physics

Question : 5 of 90

Marks: +1, -0

A capacitor C1=1.0µF is charged up to a voltage V=60V by connecting it to battery B through switch ( 1). Now C1 is disconnected from battery and connected to a circuit consisting of two uncharged capacitors C2=3.0µF and C3=6.0µF through switch ( 2), as shown in the figure. The sum of final charges on C2 and C3 is :

[15 Apr 2018 Shift 2]

20µC
40µC
36µC
54µC

Validate

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