JEE Main 15 Apr 2018 Shift 2 Solved Paper
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A disc rotates about its axis of symmetry in a horizontal plane at a steady rate of 3.5 revolutions per second. A coin placed at a distance of 1.25 cm from the axis of rotation remains at rest on the disc. The coefficient of friction between the coin and the disc is : ( g = 10 m ∕ s 2 )
[15 Apr 2018 Shift 2]
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