JEE Main 15 Apr 2018 Shift 1 Solved Paper

Section: Mathematics

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Question : 71 of 90

Marks: +1, -0

If x2+y2+siny=4, then the value of

d2y

dx2

at the point (−2,0) is:

[Main 15 April 2018 S1]

−34
−32
4
−2

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