A monochromatic beam of light has a frequency v=3/{2\pi}\times10^12Hz and is propagating along the direction {i^{∧}+j^{∧}}/\sqrt2.It is polarized along th k^{∧} direction. The acceptable form for the magnetic field is : [Main 15 April 2018 S1]

Correct Answer is : E0C(∧i−∧j)√2cos[104(∧i+∧j)√2.→r−(3×1012)t]

E_0/C(i^{∧}-j^{∧})/\sqrt2\text{\cos}[10^4(i^{∧}+j^{∧})/{\sqrt2}.r^{\to}-(3\times10^12)t]

E_0/C(i^{∧}-j^{∧})/\sqrt2\text{\cos}[10^4(i^{∧}-j^{∧})/{\sqrt2}.r^{\to}-(3\times10^12)t]

E_0/Ck^{∧}\text{\cos}[10^4(i^{∧}+j^{∧})/{\sqrt2}.r^{\to}+(3\times10^12)t]

E_0/C(i^{∧}+j^{∧}+k^{∧})/\sqrt2\text{\cos}[10^4(i^{∧}+j^{∧})/{\sqrt2}.r^{\to}-(3\times10^12)t]

JEE Main 15 Apr 2018 Shift 1 Solved Paper

Section: Physics

Question : 21 of 90

Marks: +1, -0

A monochromatic beam of light has a frequency v=

2π

×1012Hz and is propagating along the direction

∧

√2

.It is polarized along th

∧

direction. The acceptable form for the magnetic field is :

[Main 15 April 2018 S1]

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