JEE Main 12 Jan 2019 Shift 2 Solved Paper

Section: Physics

Question : 7 of 90

Marks: +1, -0

In the above circuit, C =

√3

µF , R2 = 20 Ω, L =

√3

H and R1 = 10 Ω. Current in L - R1 path is I1 and in C - R2 path it is I2. The voltage of A.Csource is given by
V = 200 √2 sin (100t) volts. The phase difference between I1 and I2 is :

[12 Jan 2019 Shift 2]

30°
0°
90°
60°

Validate

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