JEE Main 12 Jan 2019 Shift 2 Solved Paper

Exprsssion is always positve it
2m + 1 > 0 ⇒ m > -

1

2

&
D < 0 ⇒ m2 - 6m - 3 < 0
3 - √12 < m < 3 + √12 ... (iii)
∴ Common interval is
3 - √12 < m < 3 + √12
∴ Intgral value of m {0,1,2,3,4,5,6}