JEE Main 12 Jan 2019 Shift 2 Solved Paper

Section: Mathematics

Question : 41 of 90

Marks: +1, -0

If a circle of radius R passes through the origin O and intersects the coordinate axes at A and B, then the locus of the foot of perpendicular from O on AB is :

[12 Jan 2019 Shift 2]

(x2+y2)2 = 4Rx2y2
(x2+y2) (x + y) = R2xy
(x2+y2)3 = 4R2x2y2
(x2+y2)2 = 4R2x2y2

Validate

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