JEE Main 12 Jan 2019 Shift 2 Solved Paper
© examsiri.com
Question : 4 of 90
Marks:
+1,
-0
A simple harmonic motion is represented by:
y = 5(sin3πt+√ 3 cos3πt) cm
The amplitude and time period of the motion are:
y = 5(sin3πt+
The amplitude and time period of the motion are:
[12 Jan 2019 Shift 2]
Go to Question: