JEE Main 12 Jan 2019 Shift 2 Solved Paper

Section: Physics
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Question : 4 of 90
 
Marks: +1, -0
A simple harmonic motion is represented by:
y = 5(sin3πt+ 3 cos3πt) cm
The amplitude and time period of the motion are:
[12 Jan 2019 Shift 2]
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