JEE Main 12 Jan 2019 Shift 2 Solved Paper

Section: Mathematics

Question : 37 of 90

Marks: +1, -0

If the function f given by f(x) = x3 –3(a – 2) x2 +3ax + 7, for some a ∊ R is increasing in (0, 1] anddecreasing in [1, 5), then a root of the equation,

f(x)−14

(x−1)2

= 0 (x ≠ 1) is :

[12 Jan 2019 Shift 2]

Validate

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