JEE Main 12 Jan 2019 Shift 1 Solved Paper

Section: Mathematics
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Question : 36 of 90
 
Marks: +1, -0
Let Sk =
1+2+3+...+k
k
. If S12+S22 + ... + S102 =
5
12
A, then A is equal to :
[12 Jan 2019 Shift 1]
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