JEE Main 12 Apr 2019 Paper 2 Solved Paper

Section: Mathematics

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Question : 62 of 90

Marks: +1, -0

The equation of a common tangent to the curves, y2=16x and xy=−4, is

[12 Apr 2019 Shift 2]

x+y+4=0
2x−y+2=0
x−2y+16=0
x−y+4=0

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