JEE Main 12 Apr 2019 Paper 2 Solved Paper

Section: Chemistry

Question : 52 of 90

Marks: +1, -0

A solution is prepared by dissolving 0.6 g of urea ( molar mass =60 g mol‌−1) and 1 .8 g of glucose (molar mass =180 g mol‌−1) in 100 mL of water at 27°C . The osmotic pressure of the solution is : (R=0.08206‌L‌atm‌K−1‌mol−1)

[12 Apr 2019 Shift 2]

2.46 atm
1.64 atm
4.92 atm
8.2 atm

Validate

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