JEE Main 12 Apr 2019 Paper 1 Solved Paper

Section: Physics

Question : 8 of 90

Marks: +1, -0

To verify Ohm’slaw, a student connects the voltmeter across the battery as, shown in the figure. The measured voltage is plotted as a function of the current, and the following graph is obtained.

If V0 is almost zero, identify the correct statement.

[12 Apr 2019 Shift 1]

The potential difference across the battery is 1.5 V when it sends a current of 1000 mA
The value of the resistance R is 1.5 Ω
The emf of the battery is 1.5 V and the value of R is 1.5 Ω
The emf of the battery is 1.5 V and its internal resistance is 1.5 Ω

Validate

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