If {e}^{ {y}}+ {xy}= {e}, the ordered pair ( { {dy}}/{ {dx}}, { {d}^{2} {y}}/{ {dx}^{2}} ) at {x}=0 is equal to: [12 Apr 2019 Shift 1]

Correct Answer is : (−1e,1e2)

(- {1}/{ {e}},- {1}/{ {e}^{2}} )

( {1}/{ {e}},- {1}/{ {e}^{2}} )

(- {1}/{ {e}}, {1}/{ {e}^{2}} )

JEE Main 12 Apr 2019 Paper 1 Solved Paper

Section: Mathematics

Question : 77 of 90

Marks: +1, -0

If ey+xy=e, the ordered pair (

d2 y

dx2

) at x=0 is equal to:

[12 Apr 2019 Shift 1]

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