JEE Main 12 Apr 2019 Paper 1 Solved Paper

An excited He+ ion emits two photons in succession, with wavelengths 108.5 nm and 30.4 nm, in making a transition to ground state. The quantum number n, corresponding to its initial excited state is (for photon of wavelength λ , energy E=

1240‌eV

λ(in‌nm)

.