JEE Main 12 Apr 2019 Paper 1 Solved Paper

Section: Physics

Question : 29 of 90

Marks: +1, -0

When M1 gram of ice at −10°C (specific heat = 0.5 cal g−1 °C−1 is added to M2 is added to of water at 50°C, finally no ice is left and the water is at 0°C. The value of latent heat of ice, in calg−1 is:

[12 Apr 2019 Shift 1]

5 M1
M1
−50
5 M2
M1
5 M2
M1
−5
50 M2
M1
−5

Validate

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