An electromagnetic wave is represented by the electric field \overrightarrow{ {E}}= {E}_{0} \stackrel{\^}{ {n}} \sin [\\omega{t}+(6 {y}-8 {z})] . Taking unit vectors in x, y and z directions to be i^{\^}, j^{\^},k ^{\^} , the directionof propogation s ^{\^} is [12 Apr 2019 Shift 1]

Correct Answer is : ^s= −3 ^j+4 ^k5

\stackrel{\^}{ {s}}= \stackrel{\^}{-4 { {k}}+3 \stackrel{\^}{ {j}}}/{5}

\stackrel{\^}{ {s}}= \stackrel{\^}{4 { {j}}-3 \stackrel{\^}{ {j}}}/{5}

\stackrel{\^}{ {s}}= \stackrel{\^}{-3 { {j}}+4 \stackrel{\^}{ {k}}}/{5}

\stackrel{\^}{ {s}}= \stackrel{\^}{ 3 { {j}}-4 \stackrel{\^}{ {j}}}/{5}

JEE Main 12 Apr 2019 Paper 1 Solved Paper

Section: Physics

Question : 18 of 90

Marks: +1, -0

An electromagnetic wave is represented by the electric field

→

= E0

‌sin[ωt+(6 y−8 z)] . Taking unit vectors in x, y and z directions to be

, the directionof propogation

[12 Apr 2019 Shift 1]

Go to Question:

Prev Question

Next Question