JEE Main 11 Jan 2019 Shift 2 Solved Paper

Section: Chemistry

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Question : 86 of 90

Marks: +1, -0

A

4KOH,O2

→

2B (Green) + 2H2O
3B

4HCl

→

2C (Purple) + MnO2+2H2O
2B

H2O,KI

→

2A + 2KOH + D
In the above sequence of reactions,A and D respectively, are :-

[11 Jan 2019 Shift 2]

KIO3 and MnO2
KI and K2MnO4
MnO2 and KIO3
KI and KMnO4

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