Given the equilibrium constant : KC of the reaction : Cu (s) + 2Ag^{\+} (aq) → Cu^{2+} (aq) + 2Ag (s) is 10 × 10^{15} , calculate the E^\circ_{\cell} of this reaction at 298 K [2.303 {RT}/F \at 298 K = 0.059 V] [11 Jan 2019 Shift 2]

JEE Main 11 Jan 2019 Shift 2 Solved Paper

Section: Chemistry

Question : 74 of 90

Marks: +1, -0

Given the equilibrium constant :
KC of the reaction :
Cu (s) + 2Ag+ (aq) → Cu2+ (aq) + 2Ag (s) is 10 × 1015 , calculate the E°cell of this reaction at 298 K
[2.303

‌at‌298‌K=0.059V]

[11 Jan 2019 Shift 2]

0.04736 V
0.4736 V
0.4736 mV
0.04736 mV

Validate

Go to Question:

Prev Question

Next Question