JEE Main 11 Jan 2019 Shift 2 Solved Paper

Section: Mathematics

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Question : 58 of 90

Marks: +1, -0

Given

b+c

11

=

c+a

12

=

a+b

13

for a Δ ABC with usual notation. If

cosA

α

=

cosB

β

=

cosC

γ

, then the ordered triad (α, β, γ) has a value :-

[11 Jan 2019 Shift 2]

(3, 4, 5)
(19, 7, 25)
(7, 19, 25)
(5, 12, 13)

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