JEE Main 11 Jan 2019 Shift 2 Solved Paper

Section: Mathematics

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Question : 55 of 90

Marks: +1, -0

Let f (x) =

x

√a2+x2

-

d−x

√b2+(d−x)2

, x ∊ R, where a, b and d are non-zero real constants.Then :-

[11 Jan 2019 Shift 2]

f is a decreasing function of x
f is neither increasing nor decreasingfunction of x
f' is not a continuous function of x
f is an increasing function of x

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