If |\table a-b-c,2a,2a;2b,b-c-a,2b;2c,2c,c-a-b| = (a + b + c) (x + a + b + c)^2, x ≠ 0 and a + b + c ≠ 0, then x is equal to :- [11 Jan 2019 Shift 2]

Correct Answer is : –2(a + b + c)

JEE Main 11 Jan 2019 Shift 2 Solved Paper

Section: Mathematics

Question : 51 of 90

Marks: +1, -0

= (a + b + c) (x+a+b+c)2, x ≠ 0 and a + b + c ≠ 0, then x is equal to :-

[11 Jan 2019 Shift 2]

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